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onelinecrypto

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ID: 1884
标题: onelinecrypto
描述: Author : Neobeo Category : Crypto Description How to bypass this line? assert __import__('re').fullmatch(r'SEE{\w{23}}',flag:=input()) and not int.from_bytes(flag.encode(),'big')%13**37 Difficulty Medium/Hard (Insanity Check)
类型: Crypto
网站: bugku
题目链接: https://ctf.bugku.com/challenges/detail/id/2029.html
赛事: SEETF2023
年度: 2023
Flag值: SEE{luQ5xmNUKgEEDO_c5LoJCum}
writeup: https://connor-mccartney.github.io/cryptography/other/onelinecrypto-SeeTF-2023
答案错误,我要更正