[标题搜索]只能搜索题目标题，[综合搜索]支持多关键词多项目搜索（以空格分隔）。
| 序号 | Website | Type | Title | Value | Writeup | Competition | Id |
|---|---|---|---|---|---|---|---|
| 1 | BUUCTF | Web | [WMCTF2020]CFGO | W3lcomeT0WMCTF!_*Fu2^_AnT1_32E3$ | https://raw.githubusercontent.com/wm-... | WMCTF2020 | 7700 |
| 2 | XCTF | MISC | Aesop_secret | flag{DugUpADiamondADeepDarkMine} | https://blog.csdn.net/qq_53105813/art... | ISCC | 8929 |
| 3 | BUUCTF | Real | [Gitea]1.4-RCE | Gitea 1.4.0 目录穿越导致命令执行漏洞的复现步骤及验证过程 | https://blog.csdn.net/zy15667076526/a... | Gitea | 6687 |
| 4 | WgpSec | Basic-Pwn | ezlibc | 无 | https://zaoganmaqule.github.io/2024/0... | - | 14396 |
| 5 | XCTF | Reverse | crackme | 14725KCTF83690 | http://www.yxfzedu.com/article/59 | CTF | 9367 |
| 6 | NSSCTF | MISC | [yeran]GIF | flag{FuN_giF} | https://blog.csdn.net/m0_56161093/art... | - | 12807 |
| 7 | BUUCTF | Web | [N1CTF2020]Zabbix-fun | n1ctf20205bf75ab0a30dfc0c | https://blog.csdn.net/veinard_F/artic... | N1CTF2020 | 7015 |
| 8 | BUUCTF | Pwn | [DASCTF X CBCTF 2023｜无畏者先行]GuestBook | GuestBook题目的解题过程涉及利用栈溢出漏洞泄漏canary并构造ROP链获取shell，具体步骤包括通过两次输入绕过canary保护并覆盖返回地址跳转到后门函数。验证后的解题过程及答案可参考以下来源： from pwn import *模块化脚本实现canary泄漏与ROP链构造 | https://blog.csdn.net/susu_xiaosu/art... | DASCTF X CBCTF 2023｜无畏者先行 | 6384 |
| 9 | BUUCTF | DASBOOK | [第五章][5.3.7 案例解析][SWPU2019]伟大的侦探 | flag{iloveholmesandwllm} | https://cloud.tencent.com/developer/a... | 第五章 | 7920 |
| 10 | bugku | Crypto | dashdotdash | gigem{4ll_17_74k35_15_4_l177l3_5p4c3} | https://miraitowa.github.io/2019/03/2... | TAMUctf2019 | 587 |