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   [随波逐流]CTF Flags

软件版本:v1.0.0   数据版本: v20260526
序号 Website Type Title Value Writeup Competition Id
1 BUUCTF Reverse [DASCTF Apr.2023 X SU战队2023开局之战]【简单】easyRE flag{69858b56-4987-438f-a02c-5ab5c09e5138} https://oacia.dev/DASCTF-Apr-2023-X-S... DASCTF Apr.2023 X SU战队2023开局之战 6238
2 NSSCTF 文件上传 [SWPUCTF 2024 秋季新生赛]UploadBaby UploadBaby的答案 https://blog.csdn.net/2301_80148821/a... SWPUCTF 11154
3 bugku Crypto It Takes Two! flag{ef5e1582-8116-4a5d-bc8c-2c5b6d3c7c4e} https://www.cnblogs.com/sCh3n/p/17498232.html 红明谷2023 1263
4 bugku WEB Become Admin KCTF{FiN4LlY_y0u_ar3_4dm1N} https://blog.csdn.net/weixin_46245411... TamilCTF2021 945
5 BUUCTF Pwn [Windows][HITB GSEC]BABYSTACK 无 https://whereisk0shl.top/post/hitb_gs... Windows 7682
6 cyberstrikelab 目录遍历漏洞 CVE-2019-5418 CVE-2019-5418的漏洞答案为:通过构造路径穿越攻击(如../../../../etc/passwd{{)利用Ruby on Rails框架的render file参数解析缺陷,实现任意文件读取。验证后的网址为:https://www.cnblogs.com/Found404/p/14430016.html https://www.yisu.com/jc/500010.html cyberstrikelab 16979
7 ctfshow CRYPTO.内部赛 avbv编码(Easy) avbv编码(Easy)的解题过程及答案在网页2中已详细描述,通过Base58编码逆向工程和参数推导得到最终flag。验证链接可直接访问: flag{doyoulikesnow} https://cn-sec.com/archives/720145.html 内部赛 3109
8 NSSCTF ASM [HGAME 2022 week1]easyasm hgame{welc0me_to_4sm_w0rld} https://secondbc.github.io/SecondBC/2... HGAME 10597
9 BUUCTF Reverse [DASCTF X BUUOJ 五月大联动]PaperPlease DASCTF{46a4b3357e13f0755a42651250633038} https://wdraemv.github.io/2021/06/05/... DASCTF X BUUOJ 五月大联动 6348
10 NSSCTF RCE [NSSRound#28 Team]ez_php 无 https://hvang10.github.io/2025/03/22/... NSSRound#28 11348